Chemistry Podcast

Sunday, 13 November 2016

Chemistry GK Part8

Chemistry Quiz Questions with Answers - Chemistry GK

Chemistry GK by www.ChemistryNotesInfo.com
This chemistry GK part8 is based on different Chemistry MCQs asked in many competitive exams. 
This chemistry quiz contains chemistry MCQs. These are science most important questions and answers. These science quiz questions and answers are asked in many competitive exams. 

Chemistry General Knowledge MSQs

MCQ-1.  In a crystal, Atoms are located at position of :

  Maximum P.E.
  Minimum P.E.
  Zero P.E.
  Infinite P.E.

MCQ-2.  Which is not a crystalline solid :

  KCl
  CsCl
  Glass
  Rhombic S

MCQ-3.  CsCl on heating to 760K changes into the :

  Liquid
  ZnS Structure
  NaCl Structure
  None of the above

MCQ-4.  Value of the gas constant per degree per mole is approximately equal to :

  1 cal
  2 cal
  3 cal
  4 cal

MCQ-5.  Molarity is expressed as :

  Grams/Litre
  Litres/mole
  Moles/1000gram
  Moles/litre

MCQ-6.  Solubility of a gas in water depends on the :

  Pressure of gas
  Temperature
  Nature of gas
  All of the above

MCQ-7.  A 500gram tooth paste sample has the 0.2 gram fluoride concentration. Then, what is the concentration of F in the terms of ppm level :

  1000
  400
  300
  200

MCQ-8.  Molarity of the pure water is :

  44.6
  55.6
  100
  18

MCQ-9.  Solution that obeys Roults Law is the :

  Saturated
  Unsaturated
  Ideal
  Normal

MCQ-10.  Osmotic pressure of a dilute solution is directly proportional to the :

  Diffusion rate of solute
  Ionic concentration
  Flow of solvent from a concentrated to a dilute solution
  Boiling Point

We publish some chemistry general knowledge question-answer (Chemistry MCQs) to increase your chemical science GK. Science Quiz on Scientific Instruments Part 1
https://www.youtube.com/watch?v=UR9lEVw-ybk
This Science Quiz contains important GK question answers. These MCQ question answers help you to increase your general knowledge. These are important questions asked in many state & central government exams like 
Civil Services Examination
Bank PO
Indian Economic Service Examination
Staff Selection Commission
Combined Defense Services Examination
National Defense Academy Examination
Food Corporation of India Examination
IBPS PO Examination
State Bank of India - Probationary Officers
Joint Entrance Examination
State Govt. Exams
Central Government Exams
NEET
GATE 
CEED
LSAT
XAT 
CAT
UPSC
and many more...


Write your review in comments box below...


<= Chemistry GK Part7

Chemistry GK Part7

Chemistry GK

Chemistry General Knowledge

Chemistry GK by www.ChemistryNotesInfo.com

This chemistry GK part7 is based on different chemistry question and answers. These Chemistry GK Questions with Answers contains Chemistry General Knowledge Questions and Answers. Start solving these Chemistry Quiz MCQs.

MCQ-1.  The empirical formula of an acid is the CH2O2 , So its probable molecular formula is :

  C2H4O2   C3H6O4   C2H2O4   CH2O2

MCQ-2.  IF5 has which type of the hybridization :

  sp3d
  sp3d2
  sp3d3
  None of these

MCQ-3.  No. of pairs of the electrons in oxygen molecule is the :

  6
  7
  8
  16

MCQ-4.  Which is the weakest base :

  H-
  CH3-
  CH3O-
  Cl-

MCQ-5.  Which is strongest base :

  Mg(OH)2
  Al(OH)3
  NaOH
  KOH

MCQ-6.  BF3 is acid according to the :

  Bronsted and Lowry
  Lewis
  Arrhenius
  All of the above

MCQ-7.  The strongest oxidizing agent is :

  F2
  Cl2
  Br2
  I2

MCQ-8.  The strongest reducing agent is :

  K
  Mg
  Al
  Br

MCQ-9.  The strongest reducing agent is :

  HNO2
  H2S
  H2SO3
  SnCl2

MCQ-10.  Oxidation state of oxygen atom in the potassium peroxide is the :

  0
  -1/2
  -1
  -2

We publish chemistry general knowledge question and answer (Chemistry MCQs) to increase your chemical science general knowledge (GK).


Write your review in comments box below...
Like  Share  & Learn...


<= Chemistry GK Part6

Monday, 7 November 2016

Volumetric Analysis Chemistry Formulas

Volumetric Analysis

Volumetric Analysis is a quantitative chemical analysis method. In Volumetric analysis, we measure the volume of the standard solution (whose concentration is known) to know the unknown concentration of the analyte. Volumetric analysis is also called titrimetric analysis.
Volumetric Analysis - Chemistry Formula - Volumetric Titration
The basic principle of titration is “concentration of a substance in solution is measured by adding the equal amount of equivalents of a substance present in solution of known concentration”. 

Procedure of Volumetric Analysis or Titration

1. First take the material which is to be analyzed then accurately weight it in grams with careful handling and good accuracy at calibrated weighing balance.
2. Now choose a substance which will react completely and rapidly with the analyte (above weighted substance which is to be analyzed), and prepare standard solution (standard solution have known concentration) of this substance.
Titration - Volumetric Analysis
3. Fill burette with standard solution. Add this standard solution (known solution) slowly-slowly to the flask containing analyte (unknown solution). This process is known as titration. Solution present in burette is known as titrant.
4. Continue titration, means adding known solution to unknown solution till reaction completes. Remember reaction completes when all chemical constituents of analyte react with all required chemical constituents of known substance, this point when reaction completes is known as equivalence point. An indicator is added to unknown solution to detect this equivalence point. This indicator helps the chemist to visually identify the end point of titration as at end point (or near end point) indicator changes its color.
5. After getting end point, measure the volume of known standard solution consumed to get end point from burette readings.
6. Now we know the molarity of standard solution, Volume of standard solution, weight in grams of unknown solution, Volume of unknown solution, and we can calculate number of moles of titrant and then we utilize the knowledge of the equation of reaction to get the number of moles of the analyte present in unknown solution.


Similar Topics

Sunday, 6 November 2016

Gravimetric Analysis Chemistry Formulas

Gravimetric Analysis

Gravimetric Analysis is a quantitative chemical analysis method. In gravimetric analysis, we establish relationship between weights of two substances or sometimes establish relationship between weight of a substance with volume of gas or gases.
Gravimetric Analysis - Gravimetric Titration

How to Solve Problems of Gravimetric Analysis for Mass to Mass Relationship

Solve problems of gravimetric analysis for mass to mass relationship as per following instructions,
1. First of all note down the balanced equation that represent the chemical change occur.
2. Then, write the number of moles of the reactants and products below the above balanced equation, then by using respective molecular formula write the relative weights of the substances on reactant side and product side.
3. Then, by using unitary method, calculate the unknown factor.
Now you have Question what is Unitary Method?
Unitary method is math’s technique to get the solution of problem by finding the value of single unit.

How to Solve Problems of Gravimetric Analysis for Mass to Volume Relationship

Solve problems of gravimetric analysis for mass to volume relationship as per following instructions,
1. First of all note down the balanced equation that represent the chemical change occur.
2. Then, write the weights of solid substances on reactant side and product side.
3. Gases are generally not measured in mass so they are measured in volumes. So before getting weight of gas, first check that volume of gas is given at NTP (Normal Temperature and Pressure), STP (Standard Temperature and Pressure) or at other temperature and pressure.
4. With the help of ideal gas equation (PV=nRT), we can convert the volume of any gas at any temperature and pressure into its weight and vice-versa.
Ideal Gas Equation,
           PV = nRT
Also,    PV = g/M)×RT     
As mole = weight in gram/ molecular weight.
Where, P is Pressure, V is Volume, n is no. of moles, R is gas constant, T is Temperature, g is Weight in gram, M is Molecular weight.
5. Then, by using unitary method, calculate the unknown factor.

How to Solve Problems of Gravimetric Analysis for Volume to Volume Relationship

Solve problems of gravimetric analysis for volume to volume relationship as per following instructions,
1.    First of all note down the balanced equation that represent the chemical change occurs.
2.    Then, write the volume of the reactants and products below the above balanced equation, or remember “one mole of any gas occupies 22.4 liters at NTP” then by using this write volume of the gas on reactant side and product side.
Remember,
                STP means “Standard Temperature and Pressure”.
                At STP,
       Pressure = 1 bar = 0.987 atm
mm Temperature = 273 K or 0°C
NTP means “Normal Temperature and Pressure”.
At NTP,
Pressure = 1 atm
Temperature = 293 K or 20°C
3.    We can get volume of gas at NTP with the help of ideal gas equation, if volume of gas is given at other temperature or pressure.
Remember,
        Avogadro’s Law:
                            According to Avogadro’s law “Equal volume of all the gases under same condition of pressure and Temperature contain equal no. of molecules.”
4.    Then, by using unitary method, calculate the unknown factor.

Chemical Arithmetic and Chemical Stoichiometry

Chemical Arithmetic

Chemical Arithmetic and Chemical StoichiometryChemistry is mainly an experimental science, in which we study about physical properties and chemical properties of different substances and measure these properties up to highest possibility with great efforts to get results with great precision and accuracy. Results of our experimental measurements or numerical problems have-
  • Arithmetic number,
  • Unit of measurement.

Chemical Stoichiometry

Chemical stoichiometry is all about the calculation or measurement of relative quantities of the reactants and products involved in any chemical reaction. Stoichiometry utilizes the Law of Conservation of Mass or Principle of Mass Conservation so according to law of conservation of mass, "Matter is neither created nor destroyed". Which means in a chemical reaction, amount of elements remains same in starting when only reactants there and at the completion of the reaction when product formed. We always use the “Law of conservation of mass” when we balance chemical equations. 
Stoichiometry is further divided into two branches, which are-
In Stoichiometry calculations we used different formulas and rules like-

https://chemistrynotesinfo.blogspot.com

NOTE:

If error occur=> Change website url from www.chemistrynotesinfo.blogspot.in to www.chemistrynotesinfo.com